Class Solution
- java.lang.Object
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- g2301_2400.s2344_minimum_deletions_to_make_array_divisible.Solution
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public class Solution extends Object
2344 - Minimum Deletions to Make Array Divisible.Hard
You are given two positive integer arrays
nums
andnumsDivide
. You can delete any number of elements fromnums
.Return the minimum number of deletions such that the smallest element in
nums
divides all the elements ofnumsDivide
. If this is not possible, return-1
.Note that an integer
x
dividesy
ify % x == 0
.Example 1:
Input: nums = [2,3,2,4,3], numsDivide = [9,6,9,3,15]
Output: 2
Explanation:
The smallest element in [2,3,2,4,3] is 2, which does not divide all the elements of numsDivide.
We use 2 deletions to delete the elements in nums that are equal to 2 which makes nums = [3,4,3].
The smallest element in [3,4,3] is 3, which divides all the elements of numsDivide.
It can be shown that 2 is the minimum number of deletions needed.
Example 2:
Input: nums = [4,3,6], numsDivide = [8,2,6,10]
Output: -1
Explanation:
We want the smallest element in nums to divide all the elements of numsDivide.
There is no way to delete elements from nums to allow this.
Constraints:
1 <= nums.length, numsDivide.length <= 105
1 <= nums[i], numsDivide[i] <= 109
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description int
minOperations(int[] nums, int[] numsDivide)
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