Class Solution


  • public class Solution
    extends Object
    79 - Word Search.

    Medium

    Given an m x n grid of characters board and a string word, return true if word exists in the grid.

    The word can be constructed from letters of sequentially adjacent cells, where adjacent cells are horizontally or vertically neighboring. The same letter cell may not be used more than once.

    Example 1:

    Input: board = [[“A”,“B”,“C”,“E”],[“S”,“F”,“C”,“S”],[“A”,“D”,“E”,“E”]], word = “ABCCED”

    Output: true

    Example 2:

    Input: board = [[“A”,“B”,“C”,“E”],[“S”,“F”,“C”,“S”],[“A”,“D”,“E”,“E”]], word = “SEE”

    Output: true

    Example 3:

    Input: board = [[“A”,“B”,“C”,“E”],[“S”,“F”,“C”,“S”],[“A”,“D”,“E”,“E”]], word = “ABCB”

    Output: false

    Constraints:

    • m == board.length
    • n = board[i].length
    • 1 <= m, n <= 6
    • 1 <= word.length <= 15
    • board and word consists of only lowercase and uppercase English letters.

    Follow up: Could you use search pruning to make your solution faster with a larger board?

    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • exist

        public boolean exist​(char[][] board,
                             String word)