Class Solution
- java.lang.Object
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- g0401_0500.s0433_minimum_genetic_mutation.Solution
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public class Solution extends Object
433 - Minimum Genetic Mutation.Medium
A gene string can be represented by an 8-character long string, with choices from
'A'
,'C'
,'G'
, and'T'
.Suppose we need to investigate a mutation from a gene string
start
to a gene stringend
where one mutation is defined as one single character changed in the gene string.- For example,
"AACCGGTT" --> "AACCGGTA"
is one mutation.
There is also a gene bank
bank
that records all the valid gene mutations. A gene must be inbank
to make it a valid gene string.Given the two gene strings
start
andend
and the gene bankbank
, return the minimum number of mutations needed to mutate fromstart
toend
. If there is no such a mutation, return-1
.Note that the starting point is assumed to be valid, so it might not be included in the bank.
Example 1:
Input: start = “AACCGGTT”, end = “AACCGGTA”, bank = [“AACCGGTA”]
Output: 1
Example 2:
Input: start = “AACCGGTT”, end = “AAACGGTA”, bank = [“AACCGGTA”,“AACCGCTA”,“AAACGGTA”]
Output: 2
Example 3:
Input: start = “AAAAACCC”, end = “AACCCCCC”, bank = [“AAAACCCC”,“AAACCCCC”,“AACCCCCC”]
Output: 3
Constraints:
start.length == 8
end.length == 8
0 <= bank.length <= 10
bank[i].length == 8
start
,end
, andbank[i]
consist of only the characters['A', 'C', 'G', 'T']
.
- For example,
-
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Constructor Summary
Constructors Constructor Description Solution()
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