Solution (leetcode-in-java 1.21 API)

java.lang.Object
- g0501_0600.s0521_longest_uncommon_subsequence_i.Solution

```
public class Solution
extends Object
```
521 - Longest Uncommon Subsequence I.
Easy

Given two strings a and b, return the length of the longest uncommon subsequence between a and b. If the longest uncommon subsequence does not exist, return -1.

An uncommon subsequence between two strings is a string that is a subsequence of one but not the other.

A subsequence of a string s is a string that can be obtained after deleting any number of characters from s.
- For example, "abc" is a subsequence of "aebdc" because you can delete the underlined characters in "aebdc" to get "abc". Other subsequences of "aebdc" include "aebdc", "aeb", and "" (empty string).
Example 1:

Input: a = “aba”, b = “cdc”

Output: 3

Explanation: One longest uncommon subsequence is “aba” because “aba” is a subsequence of “aba” but not “cdc”. Note that “cdc” is also a longest uncommon subsequence.

Example 2:

Input: a = “aaa”, b = “bbb”

Output: 3

Explanation: The longest uncommon subsequences are “aaa” and “bbb”.

Example 3:

Input: a = “aaa”, b = “aaa”

Output: -1

Explanation: Every subsequence of string a is also a subsequence of string b. Similarly, every subsequence of string b is also a subsequence of string a.

Constraints:
- 1 <= a.length, b.length <= 100
- a and b consist of lower-case English letters.

- Constructor Summary
  
  Constructors
  Constructor Description
  
  Solution()
- Method Summary
  
  All Methods Instance Methods Concrete Methods
  Modifier and Type Method Description
  
  int findLUSlength(String a, String b)
  - Methods inherited from class java.lang.Object
    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Detail
- Solution
```
public Solution()
```

Method Detail

findLUSlength

public int findLUSlength(String a,
                         String b)