Class Solution


  • public class Solution
    extends Object
    848 - Shifting Letters.

    Medium

    You are given a string s of lowercase English letters and an integer array shifts of the same length.

    Call the shift() of a letter, the next letter in the alphabet, (wrapping around so that 'z' becomes 'a').

    • For example, shift('a') = 'b', shift('t') = 'u', and shift('z') = 'a'.

    Now for each shifts[i] = x, we want to shift the first i + 1 letters of s, x times.

    Return the final string after all such shifts to s are applied.

    Example 1:

    Input: s = “abc”, shifts = [3,5,9]

    Output: “rpl”

    Explanation: We start with “abc”.

    After shifting the first 1 letters of s by 3, we have “dbc”.

    After shifting the first 2 letters of s by 5, we have “igc”.

    After shifting the first 3 letters of s by 9, we have “rpl”, the answer.

    Example 2:

    Input: s = “aaa”, shifts = [1,2,3]

    Output: “gfd”

    Constraints:

    • 1 <= s.length <= 105
    • s consists of lowercase English letters.
    • shifts.length == s.length
    • 0 <= shifts[i] <= 109
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • shiftingLetters

        public String shiftingLetters​(String s,
                                      int[] shifts)