Class Solution


  • public class Solution
    extends Object
    1401 - Circle and Rectangle Overlapping.

    Medium

    You are given a circle represented as (radius, xCenter, yCenter) and an axis-aligned rectangle represented as (x1, y1, x2, y2), where (x1, y1) are the coordinates of the bottom-left corner, and (x2, y2) are the coordinates of the top-right corner of the rectangle.

    Return true if the circle and rectangle are overlapped otherwise return false. In other words, check if there is any point (xi, yi) that belongs to the circle and the rectangle at the same time.

    Example 1:

    Input: radius = 1, xCenter = 0, yCenter = 0, x1 = 1, y1 = -1, x2 = 3, y2 = 1

    Output: true

    Explanation: Circle and rectangle share the point (1,0).

    Example 2:

    Input: radius = 1, xCenter = 1, yCenter = 1, x1 = 1, y1 = -3, x2 = 2, y2 = -1

    Output: false

    Example 3:

    Input: radius = 1, xCenter = 0, yCenter = 0, x1 = -1, y1 = 0, x2 = 0, y2 = 1

    Output: true

    Constraints:

    • 1 <= radius <= 2000
    • -104 <= xCenter, yCenter <= 104
    • -104 <= x1 < x2 <= 104
    • -104 <= y1 < y2 <= 104
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • checkOverlap

        public boolean checkOverlap​(int radius,
                                    int xCenter,
                                    int yCenter,
                                    int x1,
                                    int y1,
                                    int x2,
                                    int y2)