Solution (leetcode-in-java 1.21 API)

java.lang.Object
- g1701_1800.s1745_palindrome_partitioning_iv.Solution

```
public class Solution
extends Object
```
1745 - Palindrome Partitioning IV.
Hard

Given a string s, return true if it is possible to split the string s into three non-empty palindromic substrings. Otherwise, return false.

A string is said to be palindrome if it the same string when reversed.

Example 1:

Input: s = “abcbdd”

Output: true

Explanation: “abcbdd” = “a” + “bcb” + “dd”, and all three substrings are palindromes.

Example 2:

Input: s = “bcbddxy”

Output: false

Explanation: s cannot be split into 3 palindromes.

Constraints:
- 3 <= s.length <= 2000
- s consists only of lowercase English letters.

- Constructor Summary
  
  Constructors
  Constructor Description
  
  Solution()
- Method Summary
  
  All Methods Instance Methods Concrete Methods
  Modifier and Type Method Description
  
  boolean checkPartitioning(String s)
  - Methods inherited from class java.lang.Object
    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Detail
- Solution
```
public Solution()
```

Method Detail

checkPartitioning

public boolean checkPartitioning(String s)