Class Solution


  • public class Solution
    extends Object
    2057 - Smallest Index With Equal Value.

    Easy

    Given a 0-indexed integer array nums, return the smallest index i of nums such that i mod 10 == nums[i], or -1 if such index does not exist.

    x mod y denotes the remainder when x is divided by y.

    Example 1:

    Input: nums = [0,1,2]

    Output: 0

    Explanation:

    i=0: 0 mod 10 = 0 == nums[0].

    i=1: 1 mod 10 = 1 == nums[1].

    i=2: 2 mod 10 = 2 == nums[2].

    All indices have i mod 10 == nums[i], so we return the smallest index 0.

    Example 2:

    Input: nums = [4,3,2,1]

    Output: 2

    Explanation:

    i=0: 0 mod 10 = 0 != nums[0].

    i=1: 1 mod 10 = 1 != nums[1].

    i=2: 2 mod 10 = 2 == nums[2].

    i=3: 3 mod 10 = 3 != nums[3].

    2 is the only index which has i mod 10 == nums[i].

    Example 3:

    Input: nums = [1,2,3,4,5,6,7,8,9,0]

    Output: -1

    Explanation: No index satisfies i mod 10 == nums[i].

    Constraints:

    • 1 <= nums.length <= 100
    • 0 <= nums[i] <= 9
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • smallestEqual

        public int smallestEqual​(int[] nums)