Package g0801_0900.s0833_find_and_replace_in_string

Class Solution

java.lang.Object

g0801_0900.s0833_find_and_replace_in_string.Solution

public class Solution
extends Object

833 - Find And Replace in String.

Medium

You are given a 0-indexed string s that you must perform k replacement operations on. The replacement operations are given as three 0-indexed parallel arrays, indices, sources, and targets, all of length k.

To complete the ith replacement operation:

1. Check if the substring sources[i] occurs at index indices[i] in the original string s.
2. If it does not occur, do nothing.
3. Otherwise if it does occur, replace that substring with targets[i].

For example, if s = "abcd", indices[i] = 0, sources[i] = "ab", and targets[i] = "eee", then the result of this replacement will be "eeecd".

All replacement operations must occur simultaneously , meaning the replacement operations should not affect the indexing of each other. The testcases will be generated such that the replacements will not overlap.

• For example, a testcase with s = "abc", indices = [0, 1], and sources = ["ab","bc"] will not be generated because the "ab" and "bc" replacements overlap.

Return the resulting string after performing all replacement operations on s.

A substring is a contiguous sequence of characters in a string.

Example 1:

Input: s = “abcd”, indices = [0, 2], sources = [“a”, “cd”], targets = [“eee”, “ffff”]

Output: “eeebffff”

Explanation: “a” occurs at index 0 in s, so we replace it with “eee”. “cd” occurs at index 2 in s, so we replace it with “ffff”.

Example 2:

Input: s = “abcd”, indices = [0, 2], sources = [“ab”,“ec”], targets = [“eee”,“ffff”]

Output: “eeecd”

Explanation: “ab” occurs at index 0 in s, so we replace it with “eee”. “ec” does not occur at index 2 in s, so we do nothing.

Constraints:

• 1 <= s.length <= 1000
• k == indices.length == sources.length == targets.length
• 1 <= k <= 100
• 0 <= indexes[i] < s.length
• 1 <= sources[i].length, targets[i].length <= 50
• s consists of only lowercase English letters.
• sources[i] and targets[i] consist of only lowercase English letters.

Constructor Summary

Constructors

Constructor	Description
Solution()

Method Summary

Modifier and Type	Method	Description
String	findReplaceString(String s, int[] indices, String[] sources, String[] targets)

Methods inherited from class java.lang.Object

clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Detail

Solution

public Solution()

Method Detail

findReplaceString

public String findReplaceString(String s,
                                int[] indices,
                                String[] sources,
                                String[] targets)