Class Solution
- java.lang.Object
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- g2501_2600.s2528_maximize_the_minimum_powered_city.Solution
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public class Solution extends Object
2528 - Maximize the Minimum Powered City.Hard
You are given a 0-indexed integer array
stations
of lengthn
, wherestations[i]
represents the number of power stations in theith
city.Each power station can provide power to every city in a fixed range. In other words, if the range is denoted by
r
, then a power station at cityi
can provide power to all citiesj
such that|i - j| <= r
and0 <= i, j <= n - 1
.- Note that
|x|
denotes absolute value. For example,|7 - 5| = 2
and|3 - 10| = 7
.
The power of a city is the total number of power stations it is being provided power from.
The government has sanctioned building
k
more power stations, each of which can be built in any city, and have the same range as the pre-existing ones.Given the two integers
r
andk
, return the maximum possible minimum power of a city, if the additional power stations are built optimally.Note that you can build the
k
power stations in multiple cities.Example 1:
Input: stations = [1,2,4,5,0], r = 1, k = 2
Output: 5
Explanation:
One of the optimal ways is to install both the power stations at city 1.
So stations will become [1,4,4,5,0].
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City 0 is provided by 1 + 4 = 5 power stations.
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City 1 is provided by 1 + 4 + 4 = 9 power stations.
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City 2 is provided by 4 + 4 + 5 = 13 power stations.
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City 3 is provided by 5 + 4 = 9 power stations.
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City 4 is provided by 5 + 0 = 5 power stations.
So the minimum power of a city is 5.
Since it is not possible to obtain a larger power, we return 5.
Example 2:
Input: stations = [4,4,4,4], r = 0, k = 3
Output: 4
Explanation: It can be proved that we cannot make the minimum power of a city greater than 4.
Constraints:
n == stations.length
1 <= n <= 105
0 <= stations[i] <= 105
0 <= r <= n - 1
0 <= k <= 109
- Note that
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Constructor Summary
Constructors Constructor Description Solution()
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