Class Solution


  • public class Solution
    extends Object
    787 - Cheapest Flights Within K Stops.

    Medium

    There are n cities connected by some number of flights. You are given an array flights where flights[i] = [fromi, toi, pricei] indicates that there is a flight from city fromi to city toi with cost pricei.

    You are also given three integers src, dst, and k, return the cheapest price from src to dst with at most k stops. If there is no such route, return -1.

    Example 1:

    Input: n = 3, flights = [[0,1,100],[1,2,100],[0,2,500]], src = 0, dst = 2, k = 1

    Output: 200

    Explanation:

    The graph is shown.

    The cheapest price from city 0 to city 2 with at most 1 stop costs 200, as marked red in the picture.

    Example 2:

    Input: n = 3, flights = [[0,1,100],[1,2,100],[0,2,500]], src = 0, dst = 2, k = 0

    Output: 500

    Explanation:

    The graph is shown.

    The cheapest price from city 0 to city 2 with at most 0 stop costs 500, as marked blue in the picture.

    Constraints:

    • 1 <= n <= 100
    • 0 <= flights.length <= (n * (n - 1) / 2)
    • flights[i].length == 3
    • 0 <= fromi, toi < n
    • fromi != toi
    • 1 <= pricei <= 104
    • There will not be any multiple flights between two cities.
    • 0 <= src, dst, k < n
    • src != dst
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • findCheapestPrice

        public int findCheapestPrice​(int n,
                                     int[][] flights,
                                     int src,
                                     int dst,
                                     int k)