Class Solution
- java.lang.Object
-
- g0901_1000.s0969_pancake_sorting.Solution
-
public class Solution extends Object
969 - Pancake Sorting.Medium
Given an array of integers
arr
, sort the array by performing a series of pancake flips.In one pancake flip we do the following steps:
- Choose an integer
k
where1 <= k <= arr.length
. - Reverse the sub-array
arr[0...k-1]
( 0-indexed ).
For example, if
arr = [3,2,1,4]
and we performed a pancake flip choosingk = 3
, we reverse the sub-array[3,2,1]
, soarr = [1,2,3,4]
after the pancake flip atk = 3
.Return an array of the
k
-values corresponding to a sequence of pancake flips that sortarr
. Any valid answer that sorts the array within10 * arr.length
flips will be judged as correct.Example 1:
Input: arr = [3,2,4,1]
Output: [4,2,4,3]
Explanation:
We perform 4 pancake flips, with k values 4, 2, 4, and 3.
Starting state: arr = [3, 2, 4, 1]
After 1st flip (k = 4): arr = [1, 4, 2, 3]
After 2nd flip (k = 2): arr = [4, 1, 2, 3]
After 3rd flip (k = 4): arr = [3, 2, 1, 4]
After 4th flip (k = 3): arr = [1, 2, 3, 4], which is sorted.
Example 2:
Input: arr = [1,2,3]
Output: []
Explanation: The input is already sorted, so there is no need to flip anything.
Note that other answers, such as [3, 3], would also be accepted.
Constraints:
1 <= arr.length <= 100
1 <= arr[i] <= arr.length
- All integers in
arr
are unique (i.e.arr
is a permutation of the integers from1
toarr.length
).
- Choose an integer
-
-
Constructor Summary
Constructors Constructor Description Solution()
-