Class Solution


  • public class Solution
    extends Object
    1480 - Running Sum of 1d Array.

    Easy

    Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]\u2026nums[i]).

    Return the running sum of nums.

    Example 1:

    Input: nums = [1,2,3,4]

    Output: [1,3,6,10]

    Explanation: Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4].

    Example 2:

    Input: nums = [1,1,1,1,1]

    Output: [1,2,3,4,5]

    Explanation: Running sum is obtained as follows: [1, 1+1, 1+1+1, 1+1+1+1, 1+1+1+1+1].

    Example 3:

    Input: nums = [3,1,2,10,1]

    Output: [3,4,6,16,17]

    Constraints:

    • 1 <= nums.length <= 1000
    • -10^6 <= nums[i] <= 10^6
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • runningSum

        public int[] runningSum​(int[] nums)