Class Solution
- java.lang.Object
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- g1501_1600.s1575_count_all_possible_routes.Solution
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public class Solution extends Object
1575 - Count All Possible Routes.Hard
You are given an array of distinct positive integers locations where
locations[i]
represents the position of cityi
. You are also given integersstart
,finish
andfuel
representing the starting city, ending city, and the initial amount of fuel you have, respectively.At each step, if you are at city
i
, you can pick any cityj
such thatj != i
and0 <= j < locations.length
and move to cityj
. Moving from cityi
to cityj
reduces the amount of fuel you have by|locations[i] - locations[j]|
. Please notice that|x|
denotes the absolute value ofx
.Notice that
fuel
cannot become negative at any point in time, and that you are allowed to visit any city more than once (includingstart
andfinish
).Return the count of all possible routes from
start
tofinish
. Since the answer may be too large, return it modulo109 + 7
.Example 1:
Input: locations = [2,3,6,8,4], start = 1, finish = 3, fuel = 5
Output: 4
Explanation: The following are all possible routes, each uses 5 units of fuel:
1 -> 3
1 -> 2 -> 3
1 -> 4 -> 3
1 -> 4 -> 2 -> 3
Example 2:
Input: locations = [4,3,1], start = 1, finish = 0, fuel = 6
Output: 5
Explanation: The following are all possible routes:
1 -> 0, used fuel = 1
1 -> 2 -> 0, used fuel = 5
1 -> 2 -> 1 -> 0, used fuel = 5
1 -> 0 -> 1 -> 0, used fuel = 3
1 -> 0 -> 1 -> 0 -> 1 -> 0, used fuel = 5
Example 3:
Input: locations = [5,2,1], start = 0, finish = 2, fuel = 3
Output: 0
Explanation: It is impossible to get from 0 to 2 using only 3 units of fuel since the shortest route needs 4 units of fuel.
Constraints:
2 <= locations.length <= 100
1 <= locations[i] <= 109
- All integers in
locations
are distinct. 0 <= start, finish < locations.length
1 <= fuel <= 200
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description int
countRoutes(int[] locations, int start, int finish, int fuel)
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