Class Solution


  • public class Solution
    extends Object
    1808 - Maximize Number of Nice Divisors.

    Hard

    You are given a positive integer primeFactors. You are asked to construct a positive integer n that satisfies the following conditions:

    • The number of prime factors of n (not necessarily distinct) is at most primeFactors.
    • The number of nice divisors of n is maximized. Note that a divisor of n is nice if it is divisible by every prime factor of n. For example, if n = 12, then its prime factors are [2,2,3], then 6 and 12 are nice divisors, while 3 and 4 are not.

    Return the number of nice divisors of n. Since that number can be too large, return it modulo 109 + 7.

    Note that a prime number is a natural number greater than 1 that is not a product of two smaller natural numbers. The prime factors of a number n is a list of prime numbers such that their product equals n.

    Example 1:

    Input: primeFactors = 5

    Output: 6

    Explanation: 200 is a valid value of n. It has 5 prime factors: [2,2,2,5,5], and it has 6 nice divisors: [10,20,40,50,100,200]. There is not other value of n that has at most 5 prime factors and more nice divisors.

    Example 2:

    Input: primeFactors = 8

    Output: 18

    Constraints:

    • 1 <= primeFactors <= 109
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • maxNiceDivisors

        public int maxNiceDivisors​(int pf)