Class Solution


  • public class Solution
    extends Object
    1920 - Build Array from Permutation.

    Easy

    Given a zero-based permutation nums ( 0-indexed ), build an array ans of the same length where ans[i] = nums[nums[i]] for each 0 <= i < nums.length and return it.

    A zero-based permutation nums is an array of distinct integers from 0 to nums.length - 1 ( inclusive ).

    Example 1:

    Input: nums = [0,2,1,5,3,4]

    Output: [0,1,2,4,5,3]

    Explanation: The array ans is built as follows:

    ans = [nums[nums[0]], nums[nums[1]], nums[nums[2]], nums[nums[3]], nums[nums[4]], nums[nums[5]]] = [nums[0], nums[2], nums[1], nums[5], nums[3], nums[4]]
    = [0,1,2,4,5,3]

    Example 2:

    Input: nums = [5,0,1,2,3,4]

    Output: [4,5,0,1,2,3]

    Explanation: The array ans is built as follows:

    ans = [nums[nums[0]], nums[nums[1]], nums[nums[2]], nums[nums[3]], nums[nums[4]], nums[nums[5]]] = [nums[5], nums[0], nums[1], nums[2], nums[3], nums[4]] = [4,5,0,1,2,3]

    Constraints:

    • 1 <= nums.length <= 1000
    • 0 <= nums[i] < nums.length
    • The elements in nums are distinct.

    Follow-up: Can you solve it without using an extra space (i.e., O(1) memory)?

    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • buildArray

        public int[] buildArray​(int[] nums)