Package g2001_2100.s2008_maximum_earnings_from_taxi

Class Solution

  • public class Solution
extends Object
    2008 - Maximum Earnings From Taxi.

    Medium

    There are n points on a road you are driving your taxi on. The n points on the road are labeled from 1 to n in the direction you are going, and you want to drive from point 1 to point n to make money by picking up passengers. You cannot change the direction of the taxi.

    The passengers are represented by a 0-indexed 2D integer array rides, where rides[i] = [starti, endi, tipi] denotes the ith passenger requesting a ride from point starti to point endi who is willing to give a tipi dollar tip.

    For each passenger i you pick up, you earn endi - starti + tipi dollars. You may only drive at most one passenger at a time.

    Given n and rides, return the maximum number of dollars you can earn by picking up the passengers optimally.

    Note: You may drop off a passenger and pick up a different passenger at the same point.

    Example 1:

    Input: n = 5, rides = [[2,5,4],[1,5,1]]

    Output: 7

    Explanation: We can pick up passenger 0 to earn 5 - 2 + 4 = 7 dollars.

    Example 2:

    Input: n = 20, rides = [[1,6,1],[3,10,2],[10,12,3],[11,12,2],[12,15,2],[13,18,1]]

    Output: 20

    Explanation: We will pick up the following passengers:

    • Drive passenger 1 from point 3 to point 10 for a profit of 10 - 3 + 2 = 9 dollars.

    • Drive passenger 2 from point 10 to point 12 for a profit of 12 - 10 + 3 = 5 dollars.

    • Drive passenger 5 from point 13 to point 18 for a profit of 18 - 13 + 1 = 6 dollars.

    We earn 9 + 5 + 6 = 20 dollars in total.

    Constraints:

    • 1 <= n <= 105
    • 1 <= rides.length <= 3 * 104
    • rides[i].length == 3
    • 1 <= starti < endi <= n
    • 1 <= tipi <= 105

    • Constructor Detail

      • Solution

        public Solution()

    • Method Detail

      • maxTaxiEarnings

        public long maxTaxiEarnings​(int n,
                            int[][] rides)