Class Solution


  • public class Solution
    extends Object
    2012 - Sum of Beauty in the Array.

    Medium

    You are given a 0-indexed integer array nums. For each index i (1 <= i <= nums.length - 2) the beauty of nums[i] equals:

    • 2, if nums[j] < nums[i] < nums[k], for all 0 <= j < i and for all i < k <= nums.length - 1.
    • 1, if nums[i - 1] < nums[i] < nums[i + 1], and the previous condition is not satisfied.
    • 0, if none of the previous conditions holds.

    Return the sum of beauty of all nums[i] where 1 <= i <= nums.length - 2.

    Example 1:

    Input: nums = [1,2,3]

    Output: 2

    Explanation: For each index i in the range 1 <= i <= 1: - The beauty of nums[1] equals 2.

    Example 2:

    Input: nums = [2,4,6,4]

    Output: 1

    Explanation: For each index i in the range 1 <= i <= 2:

    • The beauty of nums[1] equals 1.

    • The beauty of nums[2] equals 0.

    Example 3:

    Input: nums = [3,2,1]

    Output: 0

    Explanation: For each index i in the range 1 <= i <= 1: - The beauty of nums[1] equals 0.

    Constraints:

    • 3 <= nums.length <= 105
    • 1 <= nums[i] <= 105
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • sumOfBeauties

        public int sumOfBeauties​(int[] nums)