Class Solution


  • public class Solution
    extends Object
    2022 - Convert 1D Array Into 2D Array.

    Easy

    You are given a 0-indexed 1-dimensional (1D) integer array original, and two integers, m and n. You are tasked with creating a 2-dimensional (2D) array with m rows and n columns using all the elements from original.

    The elements from indices 0 to n - 1 ( inclusive ) of original should form the first row of the constructed 2D array, the elements from indices n to 2 * n - 1 ( inclusive ) should form the second row of the constructed 2D array, and so on.

    Return an m x n 2D array constructed according to the above procedure, or an empty 2D array if it is impossible.

    Example 1:

    Input: original = [1,2,3,4], m = 2, n = 2

    Output: [[1,2],[3,4]]

    Explanation: The constructed 2D array should contain 2 rows and 2 columns.

    The first group of n=2 elements in original, [1,2], becomes the first row in the constructed 2D array.

    The second group of n=2 elements in original, [3,4], becomes the second row in the constructed 2D array.

    Example 2:

    Input: original = [1,2,3], m = 1, n = 3

    Output: 1,2,3

    Explanation: The constructed 2D array should contain 1 row and 3 columns.

    Put all three elements in original into the first row of the constructed 2D array.

    Example 3:

    Input: original = [1,2], m = 1, n = 1

    Output: []

    Explanation: There are 2 elements in original.

    It is impossible to fit 2 elements in a 1x1 2D array, so return an empty 2D array.

    Constraints:

    • 1 <= original.length <= 5 * 104
    • 1 <= original[i] <= 105
    • 1 <= m, n <= 4 * 104
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • construct2DArray

        public int[][] construct2DArray​(int[] original,
                                        int m,
                                        int n)