Class Solution
- java.lang.Object
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- g2001_2100.s2055_plates_between_candles.Solution
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public class Solution extends Object
2055 - Plates Between Candles.Medium
There is a long table with a line of plates and candles arranged on top of it. You are given a 0-indexed string
s
consisting of characters'*'
and'|'
only, where a'*'
represents a plate and a'|'
represents a candle.You are also given a 0-indexed 2D integer array
queries
wherequeries[i] = [lefti, righti]
denotes the substrings[lefti…righti]
( inclusive ). For each query, you need to find the number of plates between candles that are in the substring. A plate is considered between candles if there is at least one candle to its left and at least one candle to its right in the substring.- For example,
s = "||**||**|*"
, and a query[3, 8]
denotes the substring"*||******|"
. The number of plates between candles in this substring is2
, as each of the two plates has at least one candle in the substring to its left and right.
Return an integer array
answer
whereanswer[i]
is the answer to theith
query.Example 1:
Input: s = “**|**|***|”, queries = [[2,5],[5,9]]
Output: [2,3]
Explanation: - queries[0] has two plates between candles. - queries[1] has three plates between candles.
Example 2:
Input: s = “***|**|*****|**||**|*”, queries = [[1,17],[4,5],[14,17],[5,11],[15,16]]
Output: [9,0,0,0,0]
Explanation: - queries[0] has nine plates between candles. - The other queries have zero plates between candles.
Constraints:
3 <= s.length <= 105
s
consists of'*'
and'|'
characters.1 <= queries.length <= 105
queries[i].length == 2
0 <= lefti <= righti < s.length
- For example,
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Constructor Summary
Constructors Constructor Description Solution()
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Method Detail
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platesBetweenCandles
public int[] platesBetweenCandles(String s, int[][] queries)
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