Class Solution


  • public class Solution
    extends Object
    2398 - Maximum Number of Robots Within Budget.

    Hard

    You have n robots. You are given two 0-indexed integer arrays, chargeTimes and runningCosts, both of length n. The ith robot costs chargeTimes[i] units to charge and costs runningCosts[i] units to run. You are also given an integer budget.

    The total cost of running k chosen robots is equal to max(chargeTimes) + k * sum(runningCosts), where max(chargeTimes) is the largest charge cost among the k robots and sum(runningCosts) is the sum of running costs among the k robots.

    Return the maximum number of consecutive robots you can run such that the total cost does not exceed budget.

    Example 1:

    Input: chargeTimes = [3,6,1,3,4], runningCosts = [2,1,3,4,5], budget = 25

    Output: 3

    Explanation:

    It is possible to run all individual and consecutive pairs of robots within budget.

    To obtain answer 3, consider the first 3 robots. The total cost will be max(3,6,1) + 3 * sum(2,1,3) = 6 + 3 * 6 = 24 which is less than 25.

    It can be shown that it is not possible to run more than 3 consecutive robots within budget, so we return 3.

    Example 2:

    Input: chargeTimes = [11,12,19], runningCosts = [10,8,7], budget = 19

    Output: 0

    Explanation: No robot can be run that does not exceed the budget, so we return 0.

    Constraints:

    • chargeTimes.length == runningCosts.length == n
    • 1 <= n <= 5 * 104
    • 1 <= chargeTimes[i], runningCosts[i] <= 105
    • 1 <= budget <= 1015
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • maximumRobots

        public int maximumRobots​(int[] chargeTimes,
                                 int[] runningCosts,
                                 long budget)