Class Solution
- java.lang.Object
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- g2601_2700.s2606_find_the_substring_with_maximum_cost.Solution
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public class Solution extends Object
2606 - Find the Substring With Maximum Cost.Medium
You are given a string
s
, a stringchars
of distinct characters and an integer arrayvals
of the same length aschars
.The cost of the substring is the sum of the values of each character in the substring. The cost of an empty string is considered
0
.The value of the character is defined in the following way:
- If the character is not in the string
chars
, then its value is its corresponding position (1-indexed) in the alphabet.- For example, the value of
'a'
is1
, the value of'b'
is2
, and so on. The value of'z'
is26
.
- For example, the value of
- Otherwise, assuming
i
is the index where the character occurs in the stringchars
, then its value isvals[i]
.
Return the maximum cost among all substrings of the string
s
.Example 1:
Input: s = “adaa”, chars = “d”, vals = [-1000]
Output: 2
Explanation: The value of the characters “a” and “d” is 1 and -1000 respectively. The substring with the maximum cost is “aa” and its cost is 1 + 1 = 2. It can be proven that 2 is the maximum cost.
Example 2:
Input: s = “abc”, chars = “abc”, vals = [-1,-1,-1]
Output: 0
Explanation: The value of the characters “a”, “b” and “c” is -1, -1, and -1 respectively. The substring with the maximum cost is the empty substring "" and its cost is 0. It can be proven that 0 is the maximum cost.
Constraints:
1 <= s.length <= 105
s
consist of lowercase English letters.1 <= chars.length <= 26
chars
consist of distinct lowercase English letters.vals.length == chars.length
-1000 <= vals[i] <= 1000
- If the character is not in the string
-
-
Constructor Summary
Constructors Constructor Description Solution()
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