Class Solution
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- g1801_1900.s1824_minimum_sideway_jumps.Solution
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public class Solution extends Object
1824 - Minimum Sideway Jumps.Medium
There is a 3 lane road of length
nthat consists ofn + 1points labeled from0ton. A frog starts at point0in the second lane and wants to jump to pointn. However, there could be obstacles along the way.You are given an array
obstaclesof lengthn + 1where eachobstacles[i]( ranging from 0 to 3 ) describes an obstacle on the laneobstacles[i]at pointi. Ifobstacles[i] == 0, there are no obstacles at pointi. There will be at most one obstacle in the 3 lanes at each point.- For example, if
obstacles[2] == 1, then there is an obstacle on lane 1 at point 2.
The frog can only travel from point
ito pointi + 1on the same lane if there is not an obstacle on the lane at pointi + 1. To avoid obstacles, the frog can also perform a side jump to jump to another lane (even if they are not adjacent) at the same point if there is no obstacle on the new lane.- For example, the frog can jump from lane 3 at point 3 to lane 1 at point 3.
Return the minimum number of side jumps the frog needs to reach any lane at point n starting from lane
2at point 0.Note: There will be no obstacles on points
0andn.Example 1:

Input: obstacles = [0,1,2,3,0]
Output: 2
Explanation: The optimal solution is shown by the arrows above. There are 2 side jumps (red arrows). Note that the frog can jump over obstacles only when making side jumps (as shown at point 2).
Example 2:

Input: obstacles = [0,1,1,3,3,0]
Output: 0
Explanation: There are no obstacles on lane 2. No side jumps are required.
Example 3:

Input: obstacles = [0,2,1,0,3,0]
Output: 2
Explanation: The optimal solution is shown by the arrows above. There are 2 side jumps.
Constraints:
obstacles.length == n + 11 <= n <= 5 * 1050 <= obstacles[i] <= 3obstacles[0] == obstacles[n] == 0
- For example, if
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description intminSideJumps(int[] obstacles)
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