Class Solution


  • public class Solution
    extends Object
    2551 - Put Marbles in Bags.

    Hard

    You have k bags. You are given a 0-indexed integer array weights where weights[i] is the weight of the ith marble. You are also given the integer k.

    Divide the marbles into the k bags according to the following rules:

    • No bag is empty.
    • If the ith marble and jth marble are in a bag, then all marbles with an index between the ith and jth indices should also be in that same bag.
    • If a bag consists of all the marbles with an index from i to j inclusively, then the cost of the bag is weights[i] + weights[j].

    The score after distributing the marbles is the sum of the costs of all the k bags.

    Return the difference between the maximum and minimum scores among marble distributions.

    Example 1:

    Input: weights = [1,3,5,1], k = 2

    Output: 4

    Explanation:

    The distribution [1],[3,5,1] results in the minimal score of (1+1) + (3+1) = 6.

    The distribution [1,3],[5,1], results in the maximal score of (1+3) + (5+1) = 10.

    Thus, we return their difference 10 - 6 = 4.

    Example 2:

    Input: weights = [1, 3], k = 2

    Output: 0

    Explanation: The only distribution possible is [1],[3]. Since both the maximal and minimal score are the same, we return 0.

    Constraints:

    • 1 <= k <= weights.length <= 105
    • 1 <= weights[i] <= 109
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • putMarbles

        public long putMarbles​(int[] weights,
                               int k)