Class Solution


  • public class Solution
    extends Object
    2552 - Count Increasing Quadruplets.

    Hard

    Given a 0-indexed integer array nums of size n containing all numbers from 1 to n, return the number of increasing quadruplets.

    A quadruplet (i, j, k, l) is increasing if:

    • 0 <= i < j < k < l < n, and
    • nums[i] < nums[k] < nums[j] < nums[l].

    Example 1:

    Input: nums = [1,3,2,4,5]

    Output: 2

    Explanation:

    • When i = 0, j = 1, k = 2, and l = 3, nums[i] < nums[k] < nums[j] < nums[l].

    • When i = 0, j = 1, k = 2, and l = 4, nums[i] < nums[k] < nums[j] < nums[l]. There are no other quadruplets, so we return 2.

    Example 2:

    Input: nums = [1,2,3,4]

    Output: 0

    Explanation:

    There exists only one quadruplet with i = 0, j = 1, k = 2, l = 3, but since nums[j] < nums[k], we return 0.

    Constraints:

    • 4 <= nums.length <= 4000
    • 1 <= nums[i] <= nums.length
    • All the integers of nums are unique. nums is a permutation.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • countQuadruplets

        public long countQuadruplets​(int[] nums)