Class Solution
- java.lang.Object
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- g2601_2700.s2681_power_of_heroes.Solution
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public class Solution extends Object
2681 - Power of Heroes.Hard
You are given a 0-indexed integer array
nums
representing the strength of some heroes. The power of a group of heroes is defined as follows:- Let
i0
,i1
, … ,ik
be the indices of the heroes in a group. Then, the power of this group ismax(nums[i0], nums[i1], … ,nums[ik])2 * min(nums[i0], nums[i1], … ,nums[ik])
.
Return the sum of the power of all non-empty groups of heroes possible. Since the sum could be very large, return it modulo
109 + 7
.Example 1:
Input: nums = [2,1,4]
Output: 141
Explanation:
1st group: [2] has power = 22 * 2 = 8.
2nd group: [1] has power = 12 * 1 = 1.
3rd group: [4] has power = 42 * 4 = 64.
4th group: [2,1] has power = 22 * 1 = 4.
5th group: [2,4] has power = 42 * 2 = 32.
6th group: [1,4] has power = 42 * 1 = 16.
7th group: [2,1,4] has power = 42 * 1 = 16.
The sum of powers of all groups is 8 + 1 + 64 + 4 + 32 + 16 + 16 = 141.
Example 2:
Input: nums = [1,1,1]
Output: 7
Explanation: A total of 7 groups are possible, and the power of each group will be 1. Therefore, the sum of the powers of all groups is 7.
Constraints:
1 <= nums.length <= 105
1 <= nums[i] <= 109
- Let
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description int
sumOfPower(int[] nums)
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