java.lang.Object
g0601_0700.s0696_count_binary_substrings.Solution

public class Solution extends Object
696 - Count Binary Substrings.

Easy

Give a binary string s, return the number of non-empty substrings that have the same number of 0’s and 1’s, and all the 0’s and all the 1’s in these substrings are grouped consecutively.

Substrings that occur multiple times are counted the number of times they occur.

Example 1:

Input: s = “00110011”

Output: 6

Explanation:

 There are 6 substrings that have equal number of consecutive 1's and 0's: "0011", "01", "1100", "10", "0011", and "01".
 Notice that some of these substrings repeat and are counted the number of times they occur.
 Also, "00110011" is not a valid substring because all the 0's (and 1's) are not grouped together. 

Example 2:

Input: s = “10101”

Output: 4

Explanation: There are 4 substrings: “10”, “01”, “10”, “01” that have equal number of consecutive 1’s and 0’s.

Constraints:

  • 1 <= s.length <= 105
  • s[i] is either '0' or '1'.
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • countBinarySubstrings

      public int countBinarySubstrings(String s)