Class Solution
Easy
International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows:
'a'
maps to".-"
,'b'
maps to"-..."
,'c'
maps to"-.-."
, and so on.
For convenience, the full table for the 26
letters of the English alphabet is given below:
[“.-”,“-…”,“-.-.”,“-..”,“.”,“..-.”,“–.”,“….”,“..”,“.—”,“-.-”,“.-..”,“–”,“-.”,“—”,“.–.”,“–.-”,“.-.”,“…”,“-”,“..-”,“…-”,“.–”,“-..-”,“-.–”,“–..”]
Given an array of strings words
where each word can be written as a concatenation of the Morse code of each letter.
- For example,
"cab"
can be written as"-.-..--..."
, which is the concatenation of"-.-."
,".-"
, and"-..."
. We will call such a concatenation the transformation of a word.
Return the number of different transformations among all words we have.
Example 1:
Input: words = [“gin”,“zen”,“gig”,“msg”]
Output: 2
Explanation: The transformation of each word is:
“gin” -> “–…-.”
“zen” -> “–…-.”
“gig” -> “–…–.”
“msg” -> “–…–.”
There are 2 different transformations: “–…-.” and “–…–.”.
Example 2:
Input: words = [“a”]
Output: 1
Constraints:
1 <= words.length <= 100
1 <= words[i].length <= 12
words[i]
consists of lowercase English letters.
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Constructor Summary
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Solution
public Solution()
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Method Details
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uniqueMorseRepresentations
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