java.lang.Object
g1701_1800.s1745_palindrome_partitioning_iv.Solution

public class Solution extends Object
1745 - Palindrome Partitioning IV.

Hard

Given a string s, return true if it is possible to split the string s into three non-empty palindromic substrings. Otherwise, return false.

A string is said to be palindrome if it the same string when reversed.

Example 1:

Input: s = “abcbdd”

Output: true

Explanation: “abcbdd” = “a” + “bcb” + “dd”, and all three substrings are palindromes.

Example 2:

Input: s = “bcbddxy”

Output: false

Explanation: s cannot be split into 3 palindromes.

Constraints:

  • 3 <= s.length <= 2000
  • s consists only of lowercase English letters.
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • checkPartitioning

      public boolean checkPartitioning(String s)