java.lang.Object
g2701_2800.s2707_extra_characters_in_a_string.Solution

public class Solution extends Object
2707 - Extra Characters in a String.

Medium

You are given a 0-indexed string s and a dictionary of words dictionary. You have to break s into one or more non-overlapping substrings such that each substring is present in dictionary. There may be some extra characters in s which are not present in any of the substrings.

Return the minimum number of extra characters left over if you break up s optimally.

Example 1:

Input: s = “leetscode”, dictionary = [“leet”,“code”,“leetcode”]

Output: 1

Explanation: We can break s in two substrings: “leet” from index 0 to 3 and “code” from index 5 to 8. There is only 1 unused character (at index 4), so we return 1.

Example 2:

Input: s = “sayhelloworld”, dictionary = [“hello”,“world”]

Output: 3

Explanation: We can break s in two substrings: “hello” from index 3 to 7 and “world” from index 8 to 12. The characters at indices 0, 1, 2 are not used in any substring and thus are considered as extra characters. Hence, we return 3.

Constraints:

  • 1 <= s.length <= 50
  • 1 <= dictionary.length <= 50
  • 1 <= dictionary[i].length <= 50
  • dictionary[i] and s consists of only lowercase English letters
  • dictionary contains distinct words
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • minExtraChar

      public int minExtraChar(String s, String[] dictionary)