Package g3201_3300.s3275_k_th_nearest_obstacle_queries

Class Solution

java.lang.Object
g3201_3300.s3275_k_th_nearest_obstacle_queries.Solution
public class Solution extends Object
3275 - K-th Nearest Obstacle Queries.

Medium

There is an infinite 2D plane.

You are given a positive integer k. You are also given a 2D array queries, which contains the following queries:

  • queries[i] = [x, y]: Build an obstacle at coordinate (x, y) in the plane. It is guaranteed that there is no obstacle at this coordinate when this query is made.

After each query, you need to find the distance of the kth nearest obstacle from the origin.

Return an integer array results where results[i] denotes the kth nearest obstacle after query i, or results[i] == -1 if there are less than k obstacles.

Note that initially there are no obstacles anywhere.

The distance of an obstacle at coordinate (x, y) from the origin is given by |x| + |y|.

Example 1:

Input: queries = [[1,2],[3,4],[2,3],[-3,0]], k = 2

Output: [-1,7,5,3]

Explanation:

  • Initially, there are 0 obstacles.
  • After queries[0], there are less than 2 obstacles.
  • After queries[1], there are obstacles at distances 3 and 7.
  • After queries[2], there are obstacles at distances 3, 5, and 7.
  • After queries[3], there are obstacles at distances 3, 3, 5, and 7.

Example 2:

Input: queries = [[5,5],[4,4],[3,3]], k = 1

Output: [10,8,6]

Explanation:

  • After queries[0], there is an obstacle at distance 10.
  • After queries[1], there are obstacles at distances 8 and 10.
  • After queries[2], there are obstacles at distances 6, 8, and 10.

Constraints:

  • 1 <= queries.length <= 2 * 105
  • All queries[i] are unique.
  • -109 <= queries[i][0], queries[i][1] <= 109
  • 1 <= k <= 105

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • resultsArray

      public int[] resultsArray(int[][] queries, int k)