Class Solution
java.lang.Object
g3401_3500.s3488_closest_equal_element_queries.Solution
3488 - Closest Equal Element Queries.
Medium
You are given a circular array nums
and an array queries
.
For each query i
, you have to find the following:
- The minimum distance between the element at index
queries[i]
and any other indexj
in the circular array, wherenums[j] == nums[queries[i]]
. If no such index exists, the answer for that query should be -1.
Return an array answer
of the same size as queries
, where answer[i]
represents the result for query i
.
Example 1:
Input: nums = [1,3,1,4,1,3,2], queries = [0,3,5]
Output: [2,-1,3]
Explanation:
- Query 0: The element at
queries[0] = 0
isnums[0] = 1
. The nearest index with the same value is 2, and the distance between them is 2. - Query 1: The element at
queries[1] = 3
isnums[3] = 4
. No other index contains 4, so the result is -1. - Query 2: The element at
queries[2] = 5
isnums[5] = 3
. The nearest index with the same value is 1, and the distance between them is 3 (following the circular path:5 -> 6 -> 0 -> 1
).
Example 2:
Input: nums = [1,2,3,4], queries = [0,1,2,3]
Output: [-1,-1,-1,-1]
Explanation:
Each value in nums
is unique, so no index shares the same value as the queried element. This results in -1 for all queries.
Constraints:
1 <= queries.length <= nums.length <= 105
1 <= nums[i] <= 106
0 <= queries[i] < nums.length
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Constructor Summary
Constructors -
Method Summary
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Constructor Details
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Solution
public Solution()
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Method Details
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solveQueries
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