Class Solution


  • public class Solution
    extends Object
    985 - Sum of Even Numbers After Queries\. Medium You are given an integer array `nums` and an array `queries` where queries[i] = [vali, indexi]. For each query `i`, first, apply nums[indexi] = nums[indexi] + vali, then print the sum of the even values of `nums`. Return _an integer array_ `answer` _where_ `answer[i]` _is the answer to the_ ith _query_. **Example 1:** **Input:** nums = [1,2,3,4], queries = \[\[1,0],[-3,1],[-4,0],[2,3]] **Output:** [8,6,2,4] **Explanation:** At the beginning, the array is [1,2,3,4]. After adding 1 to nums[0], the array is [2,2,3,4], and the sum of even values is 2 + 2 + 4 = 8. After adding -3 to nums[1], the array is [2,-1,3,4], and the sum of even values is 2 + 4 = 6. After adding -4 to nums[0], the array is [-2,-1,3,4], and the sum of even values is -2 + 4 = 2. After adding 2 to nums[3], the array is [-2,-1,3,6], and the sum of even values is -2 + 6 = 4. **Example 2:** **Input:** nums = [1], queries = \[\[4,0]] **Output:** [0] **Constraints:** * 1 <= nums.length <= 104 * -104 <= nums[i] <= 104 * 1 <= queries.length <= 104 * -104 <= vali <= 104 * 0 <= indexi < nums.length
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • sumEvenAfterQueries

        public int[] sumEvenAfterQueries​(int[] nums,
                                         int[][] queries)