Class Solution


  • public class Solution
    extends Object
    101 - Symmetric Tree\. Easy Given the `root` of a binary tree, _check whether it is a mirror of itself_ (i.e., symmetric around its center). **Example 1:** ![](https://assets.leetcode.com/uploads/2021/02/19/symtree1.jpg) **Input:** root = [1,2,2,3,4,4,3] **Output:** true **Example 2:** ![](https://assets.leetcode.com/uploads/2021/02/19/symtree2.jpg) **Input:** root = [1,2,2,null,3,null,3] **Output:** false **Constraints:** * The number of nodes in the tree is in the range `[1, 1000]`. * `-100 <= Node.val <= 100` **Follow up:** Could you solve it both recursively and iteratively?
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • isSymmetric

        public boolean isSymmetric​(TreeNode root)