Class Solution


  • public class Solution
    extends Object
    563 - Binary Tree Tilt\. Easy Given the `root` of a binary tree, return _the sum of every tree node's **tilt**._ The **tilt** of a tree node is the **absolute difference** between the sum of all left subtree node **values** and all right subtree node **values**. If a node does not have a left child, then the sum of the left subtree node **values** is treated as `0`. The rule is similar if the node does not have a right child. **Example 1:** ![](https://assets.leetcode.com/uploads/2020/10/20/tilt1.jpg) **Input:** root = [1,2,3] **Output:** 1 **Explanation:** Tilt of node 2 : |0-0| = 0 (no children) Tilt of node 3 : |0-0| = 0 (no children) Tilt of node 1 : |2-3| = 1 (left subtree is just left child, so sum is 2; right subtree is just right child, so sum is 3) Sum of every tilt : 0 + 0 + 1 = 1 **Example 2:** ![](https://assets.leetcode.com/uploads/2020/10/20/tilt2.jpg) **Input:** root = [4,2,9,3,5,null,7] **Output:** 15 **Explanation:** Tilt of node 3 : |0-0| = 0 (no children) Tilt of node 5 : |0-0| = 0 (no children) Tilt of node 7 : |0-0| = 0 (no children) Tilt of node 2 : |3-5| = 2 (left subtree is just left child, so sum is 3; right subtree is just right child, so sum is 5) Tilt of node 9 : |0-7| = 7 (no left child, so sum is 0; right subtree is just right child, so sum is 7) Tilt of node 4 : |(3+5+2)-(9+7)| = |10-16| = 6 (left subtree values are 3, 5, and 2, which sums to 10; right subtree values are 9 and 7, which sums to 16) Sum of every tilt : 0 + 0 + 0 + 2 + 7 + 6 = 15 **Example 3:** ![](https://assets.leetcode.com/uploads/2020/10/20/tilt3.jpg) **Input:** root = [21,7,14,1,1,2,2,3,3] **Output:** 9 **Constraints:** * The number of nodes in the tree is in the range [0, 104]. * `-1000 <= Node.val <= 1000`
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • findTilt

        public int findTilt​(TreeNode root)