Class Solution


  • public class Solution
    extends Object
    785 - Is Graph Bipartite?\. Medium There is an **undirected** graph with `n` nodes, where each node is numbered between `0` and `n - 1`. You are given a 2D array `graph`, where `graph[u]` is an array of nodes that node `u` is adjacent to. More formally, for each `v` in `graph[u]`, there is an undirected edge between node `u` and node `v`. The graph has the following properties: * There are no self-edges (`graph[u]` does not contain `u`). * There are no parallel edges (`graph[u]` does not contain duplicate values). * If `v` is in `graph[u]`, then `u` is in `graph[v]` (the graph is undirected). * The graph may not be connected, meaning there may be two nodes `u` and `v` such that there is no path between them. A graph is **bipartite** if the nodes can be partitioned into two independent sets `A` and `B` such that **every** edge in the graph connects a node in set `A` and a node in set `B`. Return `true` _if and only if it is **bipartite**_. **Example 1:** ![](https://assets.leetcode.com/uploads/2020/10/21/bi2.jpg) **Input:** graph = \[\[1,2,3],[0,2],[0,1,3],[0,2]] **Output:** false **Explanation:** There is no way to partition the nodes into two independent sets such that every edge connects a node in one and a node in the other. **Example 2:** ![](https://assets.leetcode.com/uploads/2020/10/21/bi1.jpg) **Input:** graph = \[\[1,3],[0,2],[1,3],[0,2]] **Output:** true **Explanation:** We can partition the nodes into two sets: {0, 2} and {1, 3}. **Constraints:** * `graph.length == n` * `1 <= n <= 100` * `0 <= graph[u].length < n` * `0 <= graph[u][i] <= n - 1` * `graph[u]` does not contain `u`. * All the values of `graph[u]` are **unique**. * If `graph[u]` contains `v`, then `graph[v]` contains `u`.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • isBipartite

        public boolean isBipartite​(int[][] graph)