public class Solution
extends Object
832 - Flipping an Image\.
Easy
Given an `n x n` binary matrix `image`, flip the image **horizontally** , then invert it, and return _the resulting image_.
To flip an image horizontally means that each row of the image is reversed.
* For example, flipping `[1,1,0]` horizontally results in `[0,1,1]`.
To invert an image means that each `0` is replaced by `1`, and each `1` is replaced by `0`.
* For example, inverting `[0,1,1]` results in `[1,0,0]`.
**Example 1:**
**Input:** image = \[\[1,1,0],[1,0,1],[0,0,0]]
**Output:** [[1,0,0],[0,1,0],[1,1,1]]
**Explanation:**
First reverse each row: [[0,1,1],[1,0,1],[0,0,0]].
Then, invert the image: [[1,0,0],[0,1,0],[1,1,1]]
**Example 2:**
**Input:** image = \[\[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
**Output:** [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
**Explanation:**
First reverse each row: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]].
Then invert the image: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
**Constraints:**
* `n == image.length`
* `n == image[i].length`
* `1 <= n <= 20`
* `images[i][j]` is either `0` or `1`.