Class Solution


  • public class Solution
    extends Object
    848 - Shifting Letters\. Medium You are given a string `s` of lowercase English letters and an integer array `shifts` of the same length. Call the `shift()` of a letter, the next letter in the alphabet, (wrapping around so that `'z'` becomes `'a'`). * For example, `shift('a') = 'b'`, `shift('t') = 'u'`, and `shift('z') = 'a'`. Now for each `shifts[i] = x`, we want to shift the first `i + 1` letters of `s`, `x` times. Return _the final string after all such shifts to s are applied_. **Example 1:** **Input:** s = "abc", shifts = [3,5,9] **Output:** "rpl" **Explanation:** We start with "abc". After shifting the first 1 letters of s by 3, we have "dbc". After shifting the first 2 letters of s by 5, we have "igc". After shifting the first 3 letters of s by 9, we have "rpl", the answer. **Example 2:** **Input:** s = "aaa", shifts = [1,2,3] **Output:** "gfd" **Constraints:** * 1 <= s.length <= 105 * `s` consists of lowercase English letters. * `shifts.length == s.length` * 0 <= shifts[i] <= 109
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • shiftingLetters

        public String shiftingLetters​(String s,
                                      int[] shifts)