Class Solution


  • public class Solution
    extends Object
    898 - Bitwise ORs of Subarrays\. Medium We have an array `arr` of non-negative integers. For every (contiguous) subarray `sub = [arr[i], arr[i + 1], ..., arr[j]]` (with `i <= j`), we take the bitwise OR of all the elements in `sub`, obtaining a result `arr[i] | arr[i + 1] | ... | arr[j]`. Return the number of possible results. Results that occur more than once are only counted once in the final answer **Example 1:** **Input:** arr = [0] **Output:** 1 **Explanation:** There is only one possible result: 0. **Example 2:** **Input:** arr = [1,1,2] **Output:** 3 **Explanation:** The possible subarrays are [1], [1], [2], [1, 1], [1, 2], [1, 1, 2]. These yield the results 1, 1, 2, 1, 3, 3. There are 3 unique values, so the answer is 3. **Example 3:** **Input:** arr = [1,2,4] **Output:** 6 **Explanation:** The possible results are 1, 2, 3, 4, 6, and 7. **Constraints:** * 1 <= nums.length <= 5 * 104 * 0 <= nums[i] <= 109
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • subarrayBitwiseORs

        public int subarrayBitwiseORs​(int[] arr)