Class Solution


  • public class Solution
    extends Object
    1043 - Partition Array for Maximum Sum\. Medium Given an integer array `arr`, partition the array into (contiguous) subarrays of length **at most** `k`. After partitioning, each subarray has their values changed to become the maximum value of that subarray. Return _the largest sum of the given array after partitioning. Test cases are generated so that the answer fits in a **32-bit** integer._ **Example 1:** **Input:** arr = [1,15,7,9,2,5,10], k = 3 **Output:** 84 **Explanation:** arr becomes [15,15,15,9,10,10,10] **Example 2:** **Input:** arr = [1,4,1,5,7,3,6,1,9,9,3], k = 4 **Output:** 83 **Example 3:** **Input:** arr = [1], k = 1 **Output:** 1 **Constraints:** * `1 <= arr.length <= 500` * 0 <= arr[i] <= 109 * `1 <= k <= arr.length`
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • maxSumAfterPartitioning

        public int maxSumAfterPartitioning​(int[] arr,
                                           int k)