Package g1601_1700.s1609_even_odd_tree
Class Solution
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- g1601_1700.s1609_even_odd_tree.Solution
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public class Solution extends Object
1609 - Even Odd Tree\. Medium A binary tree is named **Even-Odd** if it meets the following conditions: * The root of the binary tree is at level index `0`, its children are at level index `1`, their children are at level index `2`, etc. * For every **even-indexed** level, all nodes at the level have **odd** integer values in **strictly increasing** order (from left to right). * For every **odd-indexed** level, all nodes at the level have **even** integer values in **strictly decreasing** order (from left to right). Given the `root` of a binary tree, _return_ `true` _if the binary tree is **Even-Odd** , otherwise return_ `false`_._ **Example 1:**  **Input:** root = [1,10,4,3,null,7,9,12,8,6,null,null,2] **Output:** true **Explanation:** The node values on each level are: Level 0: [1] Level 1: [10,4] Level 2: [3,7,9] Level 3: [12,8,6,2] Since levels 0 and 2 are all odd and increasing and levels 1 and 3 are all even and decreasing, the tree is Even-Odd. **Example 2:**  **Input:** root = [5,4,2,3,3,7] **Output:** false **Explanation:** The node values on each level are: Level 0: [5] Level 1: [4,2] Level 2: [3,3,7] Node values in level 2 must be in strictly increasing order, so the tree is not Even-Odd. **Example 3:**  **Input:** root = [5,9,1,3,5,7] **Output:** false **Explanation:** Node values in the level 1 should be even integers. **Constraints:** * The number of nodes in the tree is in the range[1, 105]
. *1 <= Node.val <= 106
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Constructor Summary
Constructors Constructor Description Solution()
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Method Detail
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isEvenOddTree
public boolean isEvenOddTree(TreeNode root)
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