Class Solution


  • public class Solution
    extends Object
    1800 - Maximum Ascending Subarray Sum\. Easy Given an array of positive integers `nums`, return the _maximum possible sum of an **ascending** subarray in_ `nums`. A subarray is defined as a contiguous sequence of numbers in an array. A subarray [numsl, numsl+1, ..., numsr-1, numsr] is **ascending** if for all `i` where `l <= i < r`, numsi < numsi+1. Note that a subarray of size `1` is **ascending**. **Example 1:** **Input:** nums = [10,20,30,5,10,50] **Output:** 65 **Explanation:** [5,10,50] is the ascending subarray with the maximum sum of 65. **Example 2:** **Input:** nums = [10,20,30,40,50] **Output:** 150 **Explanation:** [10,20,30,40,50] is the ascending subarray with the maximum sum of 150. **Example 3:** **Input:** nums = [12,17,15,13,10,11,12] **Output:** 33 **Explanation:** [10,11,12] is the ascending subarray with the maximum sum of 33. **Constraints:** * `1 <= nums.length <= 100` * `1 <= nums[i] <= 100`
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • maxAscendingSum

        public int maxAscendingSum​(int[] nums)