Class Solution


  • public class Solution
    extends Object
    1862 - Sum of Floored Pairs\. Hard Given an integer array `nums`, return the sum of `floor(nums[i] / nums[j])` for all pairs of indices `0 <= i, j < nums.length` in the array. Since the answer may be too large, return it **modulo** 109 + 7. The `floor()` function returns the integer part of the division. **Example 1:** **Input:** nums = [2,5,9] **Output:** 10 **Explanation:** floor(2 / 5) = floor(2 / 9) = floor(5 / 9) = 0 floor(2 / 2) = floor(5 / 5) = floor(9 / 9) = 1 floor(5 / 2) = 2 floor(9 / 2) = 4 floor(9 / 5) = 1 We calculate the floor of the division for every pair of indices in the array then sum them up. **Example 2:** **Input:** nums = [7,7,7,7,7,7,7] **Output:** 49 **Constraints:** * 1 <= nums.length <= 105 * 1 <= nums[i] <= 105
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • sumOfFlooredPairs

        public int sumOfFlooredPairs​(int[] nums)