Class Solution


  • public class Solution
    extends Object
    2181 - Merge Nodes in Between Zeros\. Medium You are given the `head` of a linked list, which contains a series of integers **separated** by `0`'s. The **beginning** and **end** of the linked list will have `Node.val == 0`. For **every** two consecutive `0`'s, **merge** all the nodes lying in between them into a single node whose value is the **sum** of all the merged nodes. The modified list should not contain any `0`'s. Return _the_ `head` _of the modified linked list_. **Example 1:** ![](https://assets.leetcode.com/uploads/2022/02/02/ex1-1.png) **Input:** head = [0,3,1,0,4,5,2,0] **Output:** [4,11] **Explanation:** The above figure represents the given linked list. The modified list contains - The sum of the nodes marked in green: 3 + 1 = 4. - The sum of the nodes marked in red: 4 + 5 + 2 = 11. **Example 2:** ![](https://assets.leetcode.com/uploads/2022/02/02/ex2-1.png) **Input:** head = [0,1,0,3,0,2,2,0] **Output:** [1,3,4] **Explanation:** The above figure represents the given linked list. The modified list contains - The sum of the nodes marked in green: 1 = 1. - The sum of the nodes marked in red: 3 = 3. - The sum of the nodes marked in yellow: 2 + 2 = 4. **Constraints:** * The number of nodes in the list is in the range [3, 2 * 105]. * `0 <= Node.val <= 1000` * There are **no** two consecutive nodes with `Node.val == 0`. * The **beginning** and **end** of the linked list have `Node.val == 0`.
    • Constructor Detail

      • Solution

        public Solution()