Class Solution


  • public class Solution
    extends Object
    2257 - Count Unguarded Cells in the Grid\. Medium You are given two integers `m` and `n` representing a **0-indexed** `m x n` grid. You are also given two 2D integer arrays `guards` and `walls` where guards[i] = [rowi, coli] and walls[j] = [rowj, colj] represent the positions of the ith guard and jth wall respectively. A guard can see **every** cell in the four cardinal directions (north, east, south, or west) starting from their position unless **obstructed** by a wall or another guard. A cell is **guarded** if there is **at least** one guard that can see it. Return _the number of unoccupied cells that are **not** **guarded**._ **Example 1:** ![](https://assets.leetcode.com/uploads/2022/03/10/example1drawio2.png) **Input:** m = 4, n = 6, guards = \[\[0,0],[1,1],[2,3]], walls = \[\[0,1],[2,2],[1,4]] **Output:** 7 **Explanation:** The guarded and unguarded cells are shown in red and green respectively in the above diagram. There are a total of 7 unguarded cells, so we return 7. **Example 2:** ![](https://assets.leetcode.com/uploads/2022/03/10/example2drawio.png) **Input:** m = 3, n = 3, guards = \[\[1,1]], walls = \[\[0,1],[1,0],[2,1],[1,2]] **Output:** 4 **Explanation:** The unguarded cells are shown in green in the above diagram. There are a total of 4 unguarded cells, so we return 4. **Constraints:** * 1 <= m, n <= 105 * 2 <= m * n <= 105 * 1 <= guards.length, walls.length <= 5 * 104 * `2 <= guards.length + walls.length <= m * n` * `guards[i].length == walls[j].length == 2` * 0 <= rowi, rowj < m * 0 <= coli, colj < n * All the positions in `guards` and `walls` are **unique**.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • countUnguarded

        public int countUnguarded​(int m,
                                  int n,
                                  int[][] guards,
                                  int[][] walls)