Class Solution


  • public class Solution
    extends Object
    892 - Surface Area of 3D Shapes.

    Easy

    You are given an n x n grid where you have placed some 1 x 1 x 1 cubes. Each value v = grid[i][j] represents a tower of v cubes placed on top of cell (i, j).

    After placing these cubes, you have decided to glue any directly adjacent cubes to each other, forming several irregular 3D shapes.

    Return the total surface area of the resulting shapes.

    Note: The bottom face of each shape counts toward its surface area.

    Example 1:

    Input: grid = [[1,2],[3,4]]

    Output: 34

    Example 2:

    Input: grid = [[1,1,1],[1,0,1],[1,1,1]]

    Output: 32

    Example 3:

    Input: grid = [[2,2,2],[2,1,2],[2,2,2]]

    Output: 46

    Constraints:

    • n == grid.length == grid[i].length
    • 1 <= n <= 50
    • 0 <= grid[i][j] <= 50
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • surfaceArea

        public int surfaceArea​(int[][] grid)