Class Solution


  • public class Solution
    extends Object
    994 - Rotting Oranges.

    Medium

    You are given an m x n grid where each cell can have one of three values:

    • 0 representing an empty cell,
    • 1 representing a fresh orange, or
    • 2 representing a rotten orange.

    Every minute, any fresh orange that is 4-directionally adjacent to a rotten orange becomes rotten.

    Return the minimum number of minutes that must elapse until no cell has a fresh orange. If this is impossible, return -1.

    Example 1:

    Input: grid = [[2,1,1],[1,1,0],[0,1,1]]

    Output: 4

    Example 2:

    Input: grid = [[2,1,1],[0,1,1],[1,0,1]]

    Output: -1

    Explanation: The orange in the bottom left corner (row 2, column 0) is never rotten, because rotting only happens 4-directionally.

    Example 3:

    Input: grid = [[0,2]]

    Output: 0

    Explanation: Since there are already no fresh oranges at minute 0, the answer is just 0.

    Constraints:

    • m == grid.length
    • n == grid[i].length
    • 1 <= m, n <= 10
    • grid[i][j] is 0, 1, or 2.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • orangesRotting

        public int orangesRotting​(int[][] grid)