Class Solution
- java.lang.Object
-
- g1401_1500.s1409_queries_on_a_permutation_with_key.Solution
-
public class Solution extends Object
1409 - Queries on a Permutation With Key.Medium
Given the array
queries
of positive integers between1
andm
, you have to process allqueries[i]
(fromi=0
toi=queries.length-1
) according to the following rules:- In the beginning, you have the permutation
P=[1,2,3,...,m]
. - For the current
i
, find the position ofqueries[i]
in the permutationP
( indexing from 0 ) and then move this at the beginning of the permutationP.
Notice that the position ofqueries[i]
inP
is the result forqueries[i]
.
Return an array containing the result for the given
queries
.Example 1:
Input: queries = [3,1,2,1], m = 5
Output: [2,1,2,1]
Explanation: The queries are processed as follow:
For i=0: queries[i]=3, P=[1,2,3,4,5], position of 3 in P is 2 , then we move 3 to the beginning of P resulting in P=[3,1,2,4,5].
For i=1: queries[i]=1, P=[3,1,2,4,5], position of 1 in P is 1 , then we move 1 to the beginning of P resulting in P=[1,3,2,4,5].
For i=2: queries[i]=2, P=[1,3,2,4,5], position of 2 in P is 2 , then we move 2 to the beginning of P resulting in P=[2,1,3,4,5].
For i=3: queries[i]=1, P=[2,1,3,4,5], position of 1 in P is 1 , then we move 1 to the beginning of P resulting in P=[1,2,3,4,5].
Therefore, the array containing the result is [2,1,2,1].
Example 2:
Input: queries = [4,1,2,2], m = 4
Output: [3,1,2,0]
Example 3:
Input: queries = [7,5,5,8,3], m = 8
Output: [6,5,0,7,5]
Constraints:
1 <= m <= 10^3
1 <= queries.length <= m
1 <= queries[i] <= m
- In the beginning, you have the permutation
-
-
Constructor Summary
Constructors Constructor Description Solution()
-
Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description int[]
processQueries(int[] queries, int m)
-