Class Solution


  • public class Solution
    extends Object
    1409 - Queries on a Permutation With Key.

    Medium

    Given the array queries of positive integers between 1 and m, you have to process all queries[i] (from i=0 to i=queries.length-1) according to the following rules:

    • In the beginning, you have the permutation P=[1,2,3,...,m].
    • For the current i, find the position of queries[i] in the permutation P ( indexing from 0 ) and then move this at the beginning of the permutation P. Notice that the position of queries[i] in P is the result for queries[i].

    Return an array containing the result for the given queries.

    Example 1:

    Input: queries = [3,1,2,1], m = 5

    Output: [2,1,2,1]

    Explanation: The queries are processed as follow:

    For i=0: queries[i]=3, P=[1,2,3,4,5], position of 3 in P is 2 , then we move 3 to the beginning of P resulting in P=[3,1,2,4,5].

    For i=1: queries[i]=1, P=[3,1,2,4,5], position of 1 in P is 1 , then we move 1 to the beginning of P resulting in P=[1,3,2,4,5].

    For i=2: queries[i]=2, P=[1,3,2,4,5], position of 2 in P is 2 , then we move 2 to the beginning of P resulting in P=[2,1,3,4,5].

    For i=3: queries[i]=1, P=[2,1,3,4,5], position of 1 in P is 1 , then we move 1 to the beginning of P resulting in P=[1,2,3,4,5].

    Therefore, the array containing the result is [2,1,2,1].

    Example 2:

    Input: queries = [4,1,2,2], m = 4

    Output: [3,1,2,0]

    Example 3:

    Input: queries = [7,5,5,8,3], m = 8

    Output: [6,5,0,7,5]

    Constraints:

    • 1 <= m <= 10^3
    • 1 <= queries.length <= m
    • 1 <= queries[i] <= m
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • processQueries

        public int[] processQueries​(int[] queries,
                                    int m)