Solution (leetcode-in-java 1.19 API)

java.lang.Object
- g1501_1600.s1582_special_positions_in_a_binary_matrix.Solution

```
public class Solution
extends Object
```
1582 - Special Positions in a Binary Matrix.
Easy

Given an m x n binary matrix mat, return the number of special positions in mat.

A position (i, j) is called special if mat[i][j] == 1 and all other elements in row i and column j are 0 (rows and columns are 0-indexed ).

Example 1:

Input: mat = [[1,0,0],[0,0,1],[1,0,0]]

Output: 1

Explanation: (1, 2) is a special position because mat[1][2] == 1 and all other elements in row 1 and column 2 are 0.

Example 2:

Input: mat = [[1,0,0],[0,1,0],[0,0,1]]

Output: 3

Explanation: (0, 0), (1, 1) and (2, 2) are special positions.

Constraints:
- m == mat.length
- n == mat[i].length
- 1 <= m, n <= 100
- mat[i][j] is either 0 or 1.

- Constructor Summary
  
  Constructors
  Constructor Description
  
  Solution()
- Method Summary
  
  All Methods Instance Methods Concrete Methods
  Modifier and Type Method Description
  
  int numSpecial(int[][] mat)
  - Methods inherited from class java.lang.Object
    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Detail
- Solution
```
public Solution()
```

Method Detail

numSpecial

public int numSpecial(int[][] mat)