Class Solution


  • public class Solution
    extends Object
    1614 - Maximum Nesting Depth of the Parentheses.

    Easy

    A string is a valid parentheses string (denoted VPS ) if it meets one of the following:

    • It is an empty string "", or a single character not equal to "(" or ")",
    • It can be written as AB (A concatenated with B), where A and B are VPS’s, or
    • It can be written as (A), where A is a VPS.

    We can similarly define the nesting depth depth(S) of any VPS S as follows:

    • depth("") = 0
    • depth(C) = 0, where C is a string with a single character not equal to "(" or ")".
    • depth(A + B) = max(depth(A), depth(B)), where A and B are VPS’s.
    • depth("(" + A + ")") = 1 + depth(A), where A is a VPS.

    For example, "", "()()", and "()(()())" are VPS’s (with nesting depths 0, 1, and 2), and ")(" and "(()" are not VPS’s.

    Given a VPS represented as string s, return the nesting depth of s.

    Example 1:

    Input: s = “(1+(2*3)+((8)/4))+1”

    Output: 3

    Explanation: Digit 8 is inside of 3 nested parentheses in the string.

    Example 2:

    Input: s = “(1)+((2))+(((3)))”

    Output: 3

    Constraints:

    • 1 <= s.length <= 100
    • s consists of digits 0-9 and characters '+', '-', '*', '/', '(', and ')'.
    • It is guaranteed that parentheses expression s is a VPS.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • maxDepth

        public int maxDepth​(String s)